Integrals of the functional form (px+q)[√(ax²+bx+c)]dx

Express px + q = λ.(derivative of ax²+bx+c) + µ

this will give λ = p/2a and µ = q - bp/2a

This transforms the expression into

(p/2a)∫(2ax+b)[√(ax²+bx+c)]dx + [(q-bp)/2a]∫[√(ax²+bx+c)]dx