Sunday, November 9, 2008

General Solution of Trigonometrical Equations

sin θ = sin α then θ = nπ + (-1)nα, n Є Z (n belongs to Z)

cos θ = cos α then θ = 2nπ ± α, n Є Z

tan θ = tan α then θ =nπ +α, n Є Z

sin² θ = sin² α then θ =nπ ±α, n Є Z

cos² θ = cos² α then θ =nπ ±α, n Є Z

tan² θ = tan² α then θ =nπ ±α, n Є Z

cos θ = cos α and sin θ = sin α then θ =nπ+α, n Є Z

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