Wednesday, November 12, 2008

Area of a triangle

Area of a triangle = 1/2 ab sin C = (1/2) bc sin A = (1/2)ac sin B


Area of a triangle = √[s(s-a)(s-b)(s-c)]


Area of a triangle = c² sin A sin B/(2 sin c)

= a² sin B sin C/(2 sin A)

= b² sin C sin A/(2 sin B)


topic of
Properties of Triangles and circles connected with them

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