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Tuesday, November 18, 2008
Integrals of √(a²±x²) and √(x²-a²)
∫√(a²+x²)dx = (1/2) x√(a²+x²) + (1/2) a²log |x+ √(a²+x²)| +C
∫√(a²-x²) = (1/2) x√(a²-x²) + (1/2) a²sin
-1
(x/a) + C
∫√(x²-a²) = (1/2) x√(x²-a²)- (1/2) a²log |x+ √(x²-a²)| +C
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