Saturday, December 6, 2008

Eccentricity of the hyperbola

Eccentricity of the hyperbola x²/a² - y²/b² = 1

e = √(1+b²/a²)

e = √(1+(conjugate axis)²/(transverse axis)²)
Posted by at
Labels: ,

No comments:

Post a Comment

Subscribe to: Post Comments (Atom)