Tuesday, December 2, 2008

The algebra of limits

1. lim x→a [f(x) ±g(x)] = lim x→a f(x) ±lim x→ag(x)

2. lim x→a [k.f(x)] = k lim x→af(x)

3. lim x→a[f(x).g(x)] = [lim x→a f(x)][ lim x→a g(x)]

4. lim x→a [f(x)/g(x)] = [lim x→a f(x)]/[ lim x→a g(x)]
provided lim x→a g(x) ≠ 0.



5. If f(x) is l.t. g(x) then lim x→a f(x) ≤lim x→a g(x)

No comments: