JEE SYLLABUS
general solution of trigonometric equations.
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JEE Question
Let F(x) be an indefinite integral of sin^2 x.
Statement - 1
The function F(x) satisfies F(x +Pi) = F(x) for all real x.
Because
Statement - 2
sin^2 (x+ Pi) = sin^2 x for all real x.
(A) Statement – 1 is True, Statement – 2 is True; Statement – 2 is a correct explanation for statement – 1
(B) Statement – 1 is True, Statement – 2 is True; Statement – 2 is Not a correct explanation for Statement – 1.
(C) Statement – 1 is True, Statement – 2 is False
(D) Statement – 1 is False, Statement – 2 is True
answer D
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JEE 2007 Paper I
The number of solutions of the pair of equations
2sin²θ - cos2θ = 0
2cos²θ - 3sinθ = 0
in the interval [0,2π] is
(A) zero
(B) one
(C) two
(D) four
Answer: C
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